xy^2y^'=y^3-5x^3

Lösung

x y^{2} y^{^{'}} = y^{3} - 5 x^{3}

y = x 3 - 15 ln (x) + c_{1}

Schritte zur Lösung

x y^{2} y^{'} (x) = y^{3} - 5 x^{3}

Solve Bernoulli ODE:

y = x 3 - 15 ln (x) + c_{1}

y = x 3 - 15 ln (x) + c_{1}

\frac{d}{d θ} (tan^{2} (θ))

y^{^{''}} + 11 y^{^{'}} + 24 y = 0, y (0) = 0, y^{^{'}} (0) = - 7

x \to 0 lim (\frac{( 9 ^{x} - 3 ^{x} )}{x})

\int x \cdot ln^{3} (x) d x

x \to 2 lim (2 x^{2} - 3 x + 5)