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Beliebt Rechnen >

y^{''}-2y^'+y=e^t,y(0)=0,y(0)=5

Lösung

y^{^{''}} - 2 y^{^{'}} + y = e^{t}, y (0) = 0, y (0) = 5

Lösung

y = \frac{e ^{t} t ^{2}}{2} + c_{2} e^{t} t

Schritte zur Lösung

y^{''} (t) - 2 y^{'} (t) + y = e^{t}

Solve linear ODE:

y = \frac{e ^{t} t ^{2}}{2} + c_{2} e^{t} t

y = \frac{e ^{t} t ^{2}}{2} + c_{2} e^{t} t

Graph

Beliebte Beispiele

y^{''}+4y=6cos(x)

y^{^{''}} + 4 y = 6 cos (x)

y^{''}+9y^'=e^t,y(0)=0,y^'(0)=0

y^{^{''}} + 9 y^{^{'}} = e^{t}, y (0) = 0, y^{^{'}} (0) = 0

y^{''}-4y^'+4y=2x-sin(2x)

y^{^{''}} - 4 y^{^{'}} + 4 y = 2 x - sin (2 x)

y^{''}-y=3xe^xcos(2x)

y^{^{''}} - y = 3 x e^{x} cos (2 x)

y^{''}+4y^'+5y=5

y^{^{''}} + 4 y^{^{'}} + 5 y = 5