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Beliebt Rechnen >

y^{''}+2y^'=cos(2x)

Lösung

y^{^{''}} + 2 y^{^{'}} = cos (2 x)

Lösung

y = c_{1} + c_{2} e^{- 2 x} + \frac{1}{8} sin (2 x) - \frac{1}{8} cos (2 x)

Schritte zur Lösung

y^{''} (x) + 2 y^{'} (x) = cos (2 x)

Solve linear ODE:

y = c_{1} + c_{2} e^{- 2 x} + \frac{1}{8} sin (2 x) - \frac{1}{8} cos (2 x)

y = c_{1} + c_{2} e^{- 2 x} + \frac{1}{8} sin (2 x) - \frac{1}{8} cos (2 x)

Graph

Beliebte Beispiele

y^{''}+3y^'+2y=10e^{3t}

y^{^{''}} + 3 y^{^{'}} + 2 y = 10 e^{3 t}

y^{''}-6y^'+3y=xe^x

y^{^{''}} - 6 y^{^{'}} + 3 y = x e^{x}

3y^{''}+8y^'+4y=8x^2-8x+2+e^{-2x}

3 y^{^{''}} + 8 y^{^{'}} + 4 y = 8 x^{2} - 8 x + 2 + e^{- 2 x}

y^{''''}+2y^{''}+y=3+cos(3t)

y^{^{''''}} + 2 y^{^{''}} + y = 3 + cos (3 t)

y^{''}+2y^'+y=t,y(0)=1,y^'(0)=2

y^{^{''}} + 2 y^{^{'}} + y = t, y (0) = 1, y^{^{'}} (0) = 2