y^{''}-y=8

解答

y^{^{''}} - y = 8

y = c_{1} e^{t} + c_{2} e^{- t} - 8

求解步骤

y^{''} (t) - y = 8

求解线性方程:

y = c_{1} e^{t} + c_{2} e^{- t} - 8

y = c_{1} e^{t} + c_{2} e^{- t} - 8

y^{^{''}} + y = H (t) - 2 H (t - \frac{b}{2}) + H (t - b)

y^{^{''}} + 3 y^{^{'}} - 4 y = 2

y^{^{''}} + 4 y = - 5

y^{^{''}} + 2 y^{^{'}} + 4 y = 3 cos (2 t) + 4 sin (2 t)

y^{^{'''}} - 4 y^{^{''}} + 5 y^{^{'}} - 2 y = 6 e^{x} + 10 cos (x)