y^{''}+3y^'=1

Lösung

y^{^{''}} + 3 y^{^{'}} = 1

y = c_{1} + c_{2} e^{- 3 t} + \frac{t}{3}

Schritte zur Lösung

y^{''} (t) + 3 y^{'} (t) = 1

Solve linear ODE:

y = c_{1} + c_{2} e^{- 3 t} + \frac{t}{3}

y = c_{1} + c_{2} e^{- 3 t} + \frac{t}{3}

y^{^{''}} + y = 2 x

y^{^{''}} - y^{^{'}} = t e^{t}, y (0) = 2, y^{^{'}} (0) = 1

y^{^{''}} + 3 y^{^{'}} + 2 y = e^{t}

y^{^{''}} + 4 y = - 12 sin (2 x)

y^{^{'''}} - 4 y^{^{''}} = x + x e^{4 x}