y^{''}+9y=(csc(3x))/4

Lösung

y^{^{''}} + 9 y = \frac{csc ( 3 x )}{4}

y = c_{1} cos (3 x) + c_{2} sin (3 x) - \frac{1}{12} x cos (3 x) + \frac{1}{36} ln (sin (3 x)) sin (3 x)

Schritte zur Lösung

y^{''} (x) + 9 y = \frac{csc ( 3 x )}{4}

Solve linear ODE:

y = c_{1} cos (3 x) + c_{2} sin (3 x) - \frac{1}{12} x cos (3 x) + \frac{1}{36} ln (sin (3 x)) sin (3 x)

y = c_{1} cos (3 x) + c_{2} sin (3 x) - \frac{1}{12} x cos (3 x) + \frac{1}{36} ln (sin (3 x)) sin (3 x)

y^{^{''}} + 9 y = \frac{3}{2} sin (2 t), y (0) = 0, y^{^{'}} (0) = 0

4 y^{^{''}} - y = e^{\frac{x}{2}} + 8

y^{^{''}} - 4 y^{^{'}} + 4 y = e^{2 x} - 6

y^{^{''}} - y^{^{'}} - 2 y = 1 + t, y (0) = 2, y^{^{'}} (0) = 0

\frac{5}{3} y^{^{''}} + 10 y^{^{'}} + 30 y = 300