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人気のある微分積分 >

y^{''}-2y^'+2y=e^xtan(x)

解

y^{^{''}} - 2 y^{^{'}} + 2 y = e^{x} tan (x)

解

y = e^{x} (c_{1} cos (x) + c_{2} sin (x)) - e^{x} cos (x) ln (tan (x) + sec (x))

解答ステップ

y^{''} (x) - 2 y^{'} (x) + 2 y = e^{x} tan (x)

線形 ODE を解く:

y = e^{x} (c_{1} cos (x) + c_{2} sin (x)) - e^{x} cos (x) ln (tan (x) + sec (x))

y = e^{x} (c_{1} cos (x) + c_{2} sin (x)) - e^{x} cos (x) ln (tan (x) + sec (x))

グラフ

人気の例

y^{''}+2y^'+y=e^x

y^{^{''}} + 2 y^{^{'}} + y = e^{x}

(d^4+d^2)y=18x-4sin(x)

(d^{4} + d^{2}) y = 18 x - 4 sin (x)

y^{''}+6y^'+5y=12e^t,y(0)=-1,y^'(0)=7

y^{^{''}} + 6 y^{^{'}} + 5 y = 12 e^{t}, y (0) = - 1, y^{^{'}} (0) = 7

y^{''}-6y^'+9y=x^2+e^x

y^{^{''}} - 6 y^{^{'}} + 9 y = x^{2} + e^{x}

solvefor D,D(t)=(100ln(t+2))/(t+2)

so l v e f or D, D (t) = \frac{100 ln ( t + 2 )}{t + 2}