y^'=sin(x)sin(y)

Lösung

y^{^{'}} = sin (x) sin (y)

y = 2 arctan (e^{- c o s (x) + c_{1}}) + 2 πn

Schritte zur Lösung

y^{'} (x) = sin (x) sin (y)

Solve separable ODE:

y = 2 arctan (e^{- c o s (x) + c_{1}}) + 2 πn

y = 2 arctan (e^{- c o s (x) + c_{1}}) + 2 πn

\frac{d Q}{d x} = 5 x^{4} Q

\frac{d v}{d t} = 10 + 2 v

y^{^{'}} = y^{- 9} x^{9}, y (0) = 9

\frac{d y}{d x} = - 12 x^{3} y

y^{^{'}} = b \cdot y + c