y^'+y=xy

Lösung

y^{^{'}} + y = x y

y = e^{\frac{x ^{2}}{2} - x + c_{1}}

Schritte zur Lösung

y^{'} (x) + y = x y

Solve separable ODE:

y = e^{\frac{x ^{2}}{2} - x + c_{1}}

y = e^{\frac{x ^{2}}{2} - x + c_{1}}

1000 y^{^{'}} = 5000 - 100 y

y^{^{'}} = 5 e^{(x - y)}

a y - b t y^{^{'}} = 0

\frac{d y}{x} - y \frac{d x}{x ^{2}} = 0

4 + 2 \cdot cot (y) \frac{d y}{d x} = 0