derivative of 6x^2+7y^2-1=0

解

\frac{d}{d x} (6 x^{2} + 7 y^{2} - 1) = 0

y = \frac{c _{1} - 6 x ^{2} + 1}{7}, y = - \frac{c _{1} - 6 x ^{2} + 1}{7}

解答ステップ

\frac{d}{d x} (6 x^{2} + 7 y^{2} - 1) = 0

f^{^{'}} (x) = g (x)

であれば

f (x) = \int g (x) d x

6 x^{2} + 7 y^{2} - 1 = \int 0 d x

\int 0 d x = c_{1}

6 x^{2} + 7 y^{2} - 1 = c_{1}

分離する

y : y = \frac{c _{1} - 6 x ^{2} + 1}{7}, y = - \frac{c _{1} - 6 x ^{2} + 1}{7}

y = \frac{c _{1} - 6 x ^{2} + 1}{7}, y = - \frac{c _{1} - 6 x ^{2} + 1}{7}