y^'=(xe^{x+y})/y

Lösung

y^{^{'}} = \frac{x e ^{x + y}}{y}

y = - W (\frac{e ^{x} x - e ^{x} + c _{1}}{e}) - 1

Schritte zur Lösung

y^{'} (x) = \frac{x e ^{x + y}}{y}

Solve separable ODE:

y = - W (\frac{e ^{x} x - e ^{x} + c _{1}}{e}) - 1

y = - W (\frac{e ^{x} x - e ^{x} + c _{1}}{e}) - 1

\frac{d y}{d x} = (y (1 - y))

\frac{f ^{^{'}} ( x )}{f ( x )} = x e^{x}, f (0) = 4

y^{^{'}} = \frac{3 y ^{2} + 9}{( 2 x y )}

y^{^{'}} + 5 x y = x

y^{^{'}} = \frac{( ln ( x ) ) ^{3}}{x y ^{2}}