sqrt(x)y^'=e^{(6y+sqrt(x))}

Lösung

x y^{^{'}} = e^{(6 y + x)}

y = - \frac{ln ( - 12 e ^{x} - c _{1} )}{6}

Schritte zur Lösung

x y^{'} (x) = e^{(6 y + x)}

Solve separable ODE:

y = - \frac{ln ( - 12 e ^{x} - c _{1} )}{6}

y = - \frac{ln ( - 12 e ^{x} - c _{1} )}{6}

\frac{d y}{d x} + 6 y = 7, y (0) = 0

\frac{d x}{d y} x y - y^{7} = 8 y

x y^{^{'}} + y = 4

y^{^{'}} = 15 4 x y

(y^{4} + 1) d x + x y^{3} d y = 0