y^'=x^2y^{-3},y(0)=4

解答

y^{^{'}} = x^{2} y^{- 3}, y (0) = 4

y = 4 \frac{4 x ^{3}}{3} + 256

求解步骤

y^{'} (x) = x^{2} y^{- 3}

求解可分离方程:

y = 4 \frac{4 x ^{3}}{3} + 256

y = 4 \frac{4 x ^{3}}{3} + 256

y^{^{'}} + 8 y = 32

\frac{d v}{d t} = 90 - \frac{4}{100} v

x^{^{'}} = 6 x + 7

(x) y - (3 - x) y^{^{'}} - y = 0

x^{^{'}} = x \cdot sin (t)