y^'= 4/(5sqrt(xy))

Lösung

y^{^{'}} = \frac{4}{5 x y}

y = 3 \frac{144 x}{25} + \frac{36 c _{1} x}{5} + \frac{9 c _{1}^{2}}{4}

Schritte zur Lösung

y^{'} (x) = \frac{4}{5 x y}

Solve separable ODE:

y = 3 \frac{144 x}{25} + \frac{36 c _{1} x}{5} + \frac{9 c _{1}^{2}}{4}

y = 3 \frac{144 x}{25} + \frac{36 c _{1} x}{5} + \frac{9 c _{1}^{2}}{4}

y^{^{'}} = x ln (x) y n

2 x d x - y d y = 0, y = f

\frac{d y}{d x} 4 x^{3} y^{4} = 8

\frac{d y}{d t} = - 0.17 (100 - y)

\frac{( d y )}{( d x )} = \frac{( 1 )}{( 4 ) y}