u^'=5-0.5\H(t)

Lösung

u^{^{'}} = 5 - 0.5 H (t)

u (t) = \int 5 - 0.5 H (t) d t

Schritte zur Lösung

u^{'} (t) = 5 - 0.5 H (t)

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

u (t) = \int 5 - 0.5 H (t) d t

u (t) = \int 5 - 0.5 H (t) d t

f^{^{'}} (x) f (x) = x^{2} + 10 x - 5

y (4 - x^{2}) d y = (4 + y^{2}) d x

\frac{d y}{d x} + 2 x y = 25 x

x y^{^{'}} + 4 y + 8 = 0

\frac{d y}{d x} = - 3 x^{2} y