What is the solution for (dy)/(dx)y=(4sin(x))/(9-8sin(x)) ?

The solution for (dy)/(dx)y=(4sin(x))/(9-8sin(x)) is

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(dy)/(dx)y=(4sin(x))/(9-8sin(x))

\frac{d y}{d x} y = \frac{4 sin ( x )}{9 - 8 sin ( x )}

y = \frac{- 17 x + 18 arctan ( \frac{1}{17} ( 9 tan ( \frac{x}{2} ) - 8 ) ) + c _{1}}{17}, y = - \frac{- 17 x + 18 arctan ( \frac{1}{17} ( 9 tan ( \frac{x}{2} ) - 8 ) ) + c _{1}}{17}

Solution steps

\frac{d y}{d x} y = \frac{4 sin ( x )}{9 - 8 sin ( x )}

Solve separable ODE:

y = \frac{- 17 x + 18 arctan ( \frac{1}{17} ( 9 tan ( \frac{x}{2} ) - 8 ) ) + c _{1}}{17}, y = - \frac{- 17 x + 18 arctan ( \frac{1}{17} ( 9 tan ( \frac{x}{2} ) - 8 ) ) + c _{1}}{17}

y = \frac{- 17 x + 18 arctan ( \frac{1}{17} ( 9 tan ( \frac{x}{2} ) - 8 ) ) + c _{1}}{17}, y = - \frac{- 17 x + 18 arctan ( \frac{1}{17} ( 9 tan ( \frac{x}{2} ) - 8 ) ) + c _{1}}{17}

\frac{d y}{d x} y = - 3 x^{7} + \frac{3}{5} x^{4} + 568 x + 12

y y^{^{'}} = x e^{x^{2} + y}

y^{^{'}} = (1 - y^{2})^{0.5}

y^{^{'}} = y^{2} (t)

\frac{d y}{d x} x = \frac{2}{3} (y - 1)^{\frac{3}{2}}

What is the solution for (dy)/(dx)y=(4sin(x))/(9-8sin(x)) ?
The solution for (dy)/(dx)y=(4sin(x))/(9-8sin(x)) is