What is the solution for (dy)/(dx)6xy+1=0 ?

The solution for (dy)/(dx)6xy+1=0 is y=sqrt((-ln(x)+c_{1))/3},y=-sqrt((-ln(x)+c_{1))/3}

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(dy)/(dx)6xy+1=0

\frac{d y}{d x} 6 x y + 1 = 0

y = \frac{- ln ( x ) + c _{1}}{3}, y = - \frac{- ln ( x ) + c _{1}}{3}

Solution steps

\frac{d y}{d x} 6 x y + 1 = 0

Solve separable ODE:

y = \frac{- ln ( x ) + c _{1}}{3}, y = - \frac{- ln ( x ) + c _{1}}{3}

y = \frac{- ln ( x ) + c _{1}}{3}, y = - \frac{- ln ( x ) + c _{1}}{3}

(x^{2} + 6)^{\frac{1}{2}} d x + \frac{1}{x csc ( 8 y )} d y = 0

\frac{d y}{d x} = 72 \cdot y \cdot x^{7}

(x^{2} + 1) \frac{d y}{d x} + x y = 3 x, y (0) = 4

y \frac{d y}{d x} = 6 (y^{2} + 7)^{7}

\frac{1}{y} y^{^{'}} = b

What is the solution for (dy)/(dx)6xy+1=0 ?
The solution for (dy)/(dx)6xy+1=0 is y=sqrt((-ln(x)+c_{1))/3},y=-sqrt((-ln(x)+c_{1))/3}