en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular Calculus >

y^'+1/2 y=9

Solution

y^{^{'}} + \frac{1}{2} y = 9

Solution

y = - e^{\frac{- t - c _{1}}{2}} + 18

Solution steps

y^{'} (t) + \frac{1}{2} y = 9

Solve separable ODE:

y = - e^{\frac{- t - c _{1}}{2}} + 18

y = - e^{\frac{- t - c _{1}}{2}} + 18

Graph

Popular Examples

(dy)/(dx)= x/y ,y(4)=-3

\frac{d y}{d x} = \frac{x}{y}, y (4) = - 3

(dx)/(dt)=x^2+(1/81)

\frac{d x}{d t} = x^{2} + (\frac{1}{81})

2y^'-4e^{2x}y=0,y(0)=6

2 y^{^{'}} - 4 e^{2 x} y = 0, y (0) = 6

e^xy^'-e^x*y=e^x

e^{x} y^{^{'}} - e^{x} \cdot y = e^{x}

derivative of x-y^{10}= derivative of 8

\frac{d}{d x} (x - y^{10}) = \frac{d}{d x} (8)

Frequently Asked Questions (FAQ)

What is the solution for y^'+1/2 y=9 ?
The solution for y^'+1/2 y=9 is y=-e^{(-t-c_{1})/2}+18