What is the solution for y^'sec(x)=7y^2,y((9pi)/2)= 1/4 ?

The solution for y^'sec(x)=7y^2,y((9pi)/2)= 1/4 is y=-1/(7sin(x)-11)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^'sec(x)=7y^2,y((9pi)/2)= 1/4

y^{^{'}} sec (x) = 7 y^{2}, y (\frac{9 π}{2}) = \frac{1}{4}

y = - \frac{1}{7 sin ( x ) - 11}

Solution steps

y^{'} (x) sec (x) = 7 y^{2}

Solve separable ODE:

y = - \frac{1}{7 sin ( x ) - 11}

y = - \frac{1}{7 sin ( x ) - 11}

What is the solution for y^'sec(x)=7y^2,y((9pi)/2)= 1/4 ?
The solution for y^'sec(x)=7y^2,y((9pi)/2)= 1/4 is y=-1/(7sin(x)-11)