111-0.5y=55y^'

Lösung

111 - 0.5 y = 55 y^{^{'}}

y = 2 e^{\frac{- t - c _{1}}{110}} + 222

Schritte zur Lösung

111 - 0.5 y = 55 y^{'} (t)

Solve separable ODE:

y = 2 e^{\frac{- t - c _{1}}{110}} + 222

y = 2 e^{\frac{- t - c _{1}}{110}} + 222

\frac{d y}{d x} = - 2 cos (x) sin (y)

y^{^{'}} \cdot ln (y) = y

x = \frac{y}{y ^{^{'}} + y}

20 (\frac{d v}{d t}) = - (20) (32) - 0.0025 v

\frac{d y}{d x} \cdot (1 + e^{x}) = e^{x - y}