y^'=5y^{-4},y(2)=5

解答

y^{^{'}} = 5 y^{- 4}, y (2) = 5

y = 5 25 t + 3075

求解步骤

y^{'} (t) = 5 y^{- 4}

求解可分离方程:

y = 5 25 t + 3075

y = 5 25 t + 3075

- y^{^{'}} + y = 10

\frac{d y}{d x} = - \frac{3}{9} x^{5} y^{8}

e^{y} y^{^{'}} = \frac{( ln ( t ) ) ^{2}}{t}, y (1) = ln (15)

\frac{d y}{d x} = - \frac{y}{a}

\frac{d v}{d t} = 5 - 0.5 \cdot v