xdx+ye^xdy=0

Lösung

x d x + y e^{x} d y = 0

y = \frac{2 x + 2 + 2 c _{1} e ^{x}}{e ^{x}}, y = - \frac{2 x + 2 + 2 c _{1} e ^{x}}{e ^{x}}

Schritte zur Lösung

x d x + y e^{x} d y = 0

Solve separable ODE:

y = \frac{2 x + 2 + 2 c _{1} e ^{x}}{e ^{x}}, y = - \frac{2 x + 2 + 2 c _{1} e ^{x}}{e ^{x}}

y = \frac{2 x + 2 + 2 c _{1} e ^{x}}{e ^{x}}, y = - \frac{2 x + 2 + 2 c _{1} e ^{x}}{e ^{x}}

\frac{8 t}{y} d y + (8 ln (y) + 5) d t = 0

y^{^{'}} = 6 + 3 y

y^{2} y^{^{'}} = \frac{x ^{3} y ^{3}}{x ^{4} - 6}

d y = 6 e^{2 x - y} d x

\frac{d y}{d x} - x (y^{2}) = 0