y^'= 1/(sin(y))

Lösung

y^{^{'}} = \frac{1}{sin ( y )}

y = arccos (- t - c_{1}) + 2 πn, y = - arccos (- t - c_{1}) + 2 πn

Schritte zur Lösung

y^{'} (t) = \frac{1}{sin ( y )}

Solve separable ODE:

y = arccos (- t - c_{1}) + 2 πn, y = - arccos (- t - c_{1}) + 2 πn

y = arccos (- t - c_{1}) + 2 πn, y = - arccos (- t - c_{1}) + 2 πn

\frac{d x}{d t} = 8 x t^{4}

d y = \frac{( y + 7 )}{( x + 4 )} d x

y^{^{'}} = (x + 1) e^{y}

\frac{d y}{d t} = \frac{- c ^{2} 2 g y}{a ^{2}}

(v + 1) (v d x + x d v) = 0