(dN)/(dt)+N=N*te^{t+2}

Lösung

\frac{d N}{d t} + N = N \cdot t e^{t + 2}

N = e^{e^{2} (e^{t} t - e^{t}) - t + c_{1}}

Schritte zur Lösung

\frac{d N}{d t} + N = N \cdot t e^{t + 2}

Solve separable ODE:

N = e^{e^{2} (e^{t} t - e^{t}) - t + c_{1}}

N = e^{e^{2} (e^{t} t - e^{t}) - t + c_{1}}

y^{^{'}} - 3 y sin (3 t) = - 3 sin (3 t), y (\frac{π}{6}) = 2

y^{^{'}} = \frac{y ^{2}}{4}

\frac{d P}{d t} = 0.015 P

\frac{d x}{d t} = 7 - x

\frac{d y}{d t} = 550 - 0.0055 y