dy=(x-1)dx+y(x-1)dx

Lösung

d y = (x - 1) d x + y (x - 1) d x

y = e^{- x + \frac{x ^{2}}{2} + c_{1}} - 1

Schritte zur Lösung

d y = (x - 1) d x + y (x - 1) d x

Solve separable ODE:

y = e^{- x + \frac{x ^{2}}{2} + c_{1}} - 1

y = e^{- x + \frac{x ^{2}}{2} + c_{1}} - 1

\frac{d y}{d x} = (1 + 4 x) (y)

e^{x + y} d y - d x = 0

\frac{1}{y} \cdot \frac{d y}{d x} = 10

\frac{d x}{d y} = 0.2 x y

y^{^{'}} + \frac{3}{2} y = \frac{3}{2}