derivative of xy^4=5

Lösung

\frac{d}{d x} (x y^{4}) = 5

y = \frac{5 x + c _{1}}{x}, y = - \frac{5 x + c _{1}}{x}, y = i 4 \frac{5 x + c _{1}}{x}, y = - i 4 \frac{5 x + c _{1}}{x}

Schritte zur Lösung

\frac{d}{d x} (x y^{4}) = 5

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

x y^{4} = \int 5 d x

\int 5 d x = 5 x + c_{1}

x y^{4} = 5 x + c_{1}

Isoliere

y : y = \frac{5 x + c _{1}}{x}, y = - \frac{5 x + c _{1}}{x}, y = i 4 \frac{5 x + c _{1}}{x}, y = - i 4 \frac{5 x + c _{1}}{x}

y = \frac{5 x + c _{1}}{x}, y = - \frac{5 x + c _{1}}{x}, y = i 4 \frac{5 x + c _{1}}{x}, y = - i 4 \frac{5 x + c _{1}}{x}

P^{^{'}} = 0.2 P + 100

\frac{d y}{d x} + 6 x^{5} y = 0

\frac{d y}{d x} y = ln (5) x^{5}

y^{^{'}} = - 2 x csc (y)

\frac{d P}{d t} = \frac{3}{2} P