y^'-(t^5)/y =0

Lösung

y^{^{'}} - \frac{t ^{5}}{y} = 0

y = \frac{t ^{6}}{3} + c_{1}, y = - \frac{t ^{6}}{3} + c_{1}

Schritte zur Lösung

y^{'} (t) - \frac{t ^{5}}{y} = 0

Solve separable ODE:

y = \frac{t ^{6}}{3} + c_{1}, y = - \frac{t ^{6}}{3} + c_{1}

y = \frac{t ^{6}}{3} + c_{1}, y = - \frac{t ^{6}}{3} + c_{1}

(x^{2} + x) y^{^{'}} + y^{2} = x y^{2}

y^{^{'}} = y (\frac{a}{x ^{2}} + b x)

\frac{d y}{d t} = 0.48 - \frac{y}{240}

f (x) = f^{^{'}} (x) (4 x + 9)^{5}

\frac{d y}{d x} = - 7 (- 4 - y)