sec(x)y^'+y=2

Lösung

sec (x) y^{^{'}} + y = 2

y = - e^{- s i n (x) - c_{1}} + 2

Schritte zur Lösung

sec (x) y^{'} (x) + y = 2

Solve separable ODE:

y = - e^{- s i n (x) - c_{1}} + 2

y = - e^{- s i n (x) - c_{1}} + 2

\frac{d y}{d x} = (1 - y) \cdot cos (x)

(2 x + 3) y^{^{'}} = x y (2 x + 3)^{\frac{1}{2}}

1 + y^{2} - x y^{^{'}} = 0

e \frac{1}{x} \frac{d y}{d x} + 4 y = 2

y^{^{'}} = \frac{3 x}{y} 1 + y^{2}