derivative of x^2+y^2=1

Lösung

\frac{d}{d x} (x^{2} + y^{2}) = 1

y = x + c_{1} - x^{2}, y = - x + c_{1} - x^{2}

Schritte zur Lösung

\frac{d}{d x} (x^{2} + y^{2}) = 1

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

x^{2} + y^{2} = \int 1 d x

\int 1 d x = x + c_{1}

x^{2} + y^{2} = x + c_{1}

Isoliere

y : y = x + c_{1} - x^{2}, y = - x + c_{1} - x^{2}

y = x + c_{1} - x^{2}, y = - x + c_{1} - x^{2}

\frac{d y}{d x} = \frac{x}{y ^{21}}

d u = - 12 t^{- 4} d t

d x - 13 x y d y = 6 y d y

\frac{d y}{d x} = \frac{- y}{x ^{2}}

y 1 - x^{2} y^{^{'}} + 1 - y^{2} = 0