y^'=(-x-xy)/(y+xy)

Lösung

y^{^{'}} = \frac{- x - x y}{y + x y}

y = - W (- \frac{1}{e ^{- x + c_{1} - 1} ( x + 1 )}) - 1

Schritte zur Lösung

y^{'} (x) = \frac{- x - x y}{y + x y}

Solve separable ODE:

y = - W (- \frac{1}{e ^{- x + c_{1} - 1} ( x + 1 )}) - 1

y = - W (- \frac{1}{e ^{- x + c_{1} - 1} ( x + 1 )}) - 1

x y y^{^{'}} = ln (x)

\frac{d y}{d t} - 3 y = 0

\frac{d y}{d x} = (x - 7) e^{- 2 y}, y (7) = ln (7)

\frac{d y}{d t} = 0.2 y

y e^{- x} y^{^{'}} = x