What is the integral of (e^{ln(1-t)})/(1-t) ?

The integral of (e^{ln(1-t)})/(1-t) is t+C

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integral of (e^{ln(1-t)})/(1-t)

\int \frac{e ^{l n (1 - t)}}{1 - t} d t

t + C

Solution steps

\int \frac{e ^{l n (1 - t)}}{1 - t} d t

\frac{e ^{l n (1 - t)}}{1 - t} = 1

= \int 1 d t

Integral of a constant:

\int a d x = a x

= 1 \cdot t

Simplify

= t

Add a constant to the solution

= t + C

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\frac{d}{d x} (x e^{x} ln (x))

d er i v a t i v e f (x) = 1 - y^{2}

What is the integral of (e^{ln(1-t)})/(1-t) ?
The integral of (e^{ln(1-t)})/(1-t) is t+C