y^'=2x^3y

Lösung

y^{^{'}} = 2 x^{3} y

y = e^{\frac{x ^{4}}{2} + c_{1}}

Schritte zur Lösung

y^{'} (x) = 2 x^{3} y

Solve separable ODE:

y = e^{\frac{x ^{4}}{2} + c_{1}}

y = e^{\frac{x ^{4}}{2} + c_{1}}

y^{^{'}} y = t, y (3) = - 3

\frac{d x}{d y} = e^{2 x + 3 y}, x (0) = 1

(3 x - 2) d x + (4 y + b) d y = 0

y^{^{'}} = \frac{( 3 t ^{2} )}{4 + 2 y}

y^{^{'}} = \frac{1}{2} (y^{2} - 1), y (0) = 6