(dx)/(dy)=y-4xy

解答

\frac{d x}{d y} = y - 4 x y

x = \frac{e ^{- 2 y^{2} + c_{1}}}{4} + \frac{1}{4}

求解步骤

\frac{d x}{d y} = y - 4 x y

求解可分离方程:

x = \frac{e ^{- 2 y^{2} + c_{1}}}{4} + \frac{1}{4}

x = \frac{e ^{- 2 y^{2} + c_{1}}}{4} + \frac{1}{4}

\frac{d y}{d t} + 2 (t + 1) y^{2} = 0, y (0) = - \frac{1}{15}

10 y^{^{'}} - 2 y - 63 = 9 y^{^{'}}

y^{5} \frac{d y}{d x} = 4 x^{4} y^{6} - 12 x^{4}

y^{^{'}} + tan (4 \cdot x) y = 0

2 y^{^{'}} = y^{3} cos (x), y (0) = (1 - sin (x))^{- \frac{1}{2}}