y^{''}-2y^'+50y=0,y(0)= 3/2 ,y^'(0)=-9

Lösung

y^{^{''}} - 2 y^{^{'}} + 50 y = 0, y (0) = \frac{3}{2}, y^{^{'}} (0) = - 9

y = e^{t} (\frac{3}{2} cos (7 t) - \frac{3}{2} sin (7 t))

Schritte zur Lösung

y^{''} (t) - 2 y^{'} (t) + 50 y = 0

Solve linear ODE:

y = e^{t} (\frac{3}{2} cos (7 t) - \frac{3}{2} sin (7 t))

y = e^{t} (\frac{3}{2} cos (7 t) - \frac{3}{2} sin (7 t))

\int_{0}^{1 - x} 24 y (1 - x - y) d y

d er i v a t i v e 4 y^{2}

t an g e n t y = \frac{6 x}{x + 3}, (- 1, - 3)

d er i v a t i v e f (x) = \frac{2 x}{x ^{2} - 8}

\int \frac{1}{t ^{2} - 2 t + 5} d t