sin(3x)dx+2y*cos^3(3x)dy=0

Lösung

sin (3 x) d x + 2 y \cdot cos^{3} (3 x) d y = 0

y = \frac{- tan ^{2} ( 3 x ) + c _{1}}{6}, y = - \frac{- tan ^{2} ( 3 x ) + c _{1}}{6}

Schritte zur Lösung

sin (3 x) d x + 2 y \cdot cos^{3} (3 x) d y = 0

Solve separable ODE:

y = \frac{- tan ^{2} ( 3 x ) + c _{1}}{6}, y = - \frac{- tan ^{2} ( 3 x ) + c _{1}}{6}

y = \frac{- tan ^{2} ( 3 x ) + c _{1}}{6}, y = - \frac{- tan ^{2} ( 3 x ) + c _{1}}{6}

\frac{d y}{d x} y x + 1 = 4

y^{2} - \frac{y ^{^{'}}}{x} = 0

\frac{d y}{d x} x y + 2 ey = 2 e

\frac{d z}{d t} + e^{(t + z)} = 0

y^{^{'}} = 4 y - 5