y^'=(5x^2-1)/(5+3y)

Lösung

y^{^{'}} = \frac{5 x ^{2} - 1}{5 + 3 y}

y = \frac{- 5 + - 2 ( - 5 x ^{3} + 3 x - c _{1} ) + 25}{3}, y = - \frac{- 2 ( - 5 x ^{3} + 3 x - c _{1} ) + 25 + 5}{3}

Schritte zur Lösung

y^{'} (x) = \frac{5 x ^{2} - 1}{5 + 3 y}

Solve separable ODE:

y = \frac{- 5 + - 2 ( - 5 x ^{3} + 3 x - c _{1} ) + 25}{3}, y = - \frac{- 2 ( - 5 x ^{3} + 3 x - c _{1} ) + 25 + 5}{3}

y = \frac{- 5 + - 2 ( - 5 x ^{3} + 3 x - c _{1} ) + 25}{3}, y = - \frac{- 2 ( - 5 x ^{3} + 3 x - c _{1} ) + 25 + 5}{3}

y^{^{'}} = e^{2 y} sin (x)

\frac{d y}{d t} = t^{2} y + 1 + y + t^{2}

e^{x + y} y^{^{'}} = x, y (0) = ln (2)

y^{^{'}} = y + 5

(x ln (x^{2})) y^{^{'}} = 2 y