e^yy^'=4,y(0)=2

Lösung

e^{y} y^{^{'}} = 4, y (0) = 2

y = ln (4 t + e^{2})

Schritte zur Lösung

e^{y} y^{'} (t) = 4

Solve separable ODE:

y = ln (4 t + e^{2})

y = ln (4 t + e^{2})

y^{^{'}} = x^{2} + x^{2} y^{2}

(y + 1) (t^{2} + 1) = t y^{^{'}}

x y^{^{'}} - 5 y = 0

\frac{d y}{d x} = x^{6} (y - 4), y (0) = 6

y^{^{'}} = \frac{( 1 - x )}{y}, y (1) = 1