y^'-3y=2

Lösung

y^{^{'}} - 3 y = 2

y = \frac{e ^{3 t + c_{1}}}{3} - \frac{2}{3}

Schritte zur Lösung

y^{'} (t) - 3 y = 2

Solve separable ODE:

y = \frac{e ^{3 t + c_{1}}}{3} - \frac{2}{3}

y = \frac{e ^{3 t + c_{1}}}{3} - \frac{2}{3}

y + y^{^{'}} - 2 y = 0

(2 x y) d x = (3 - x^{2}) d y

y^{^{'}} = \frac{2 x}{y ^{2}}

\frac{d y}{d x} = 8 y (- 3 - y)

\frac{d y}{d x} = ((1 + 2 x) y)