(dx)/(dt)=tsqrt(x)

Lösung

\frac{d x}{d t} = t x

x = \frac{t ^{4}}{16} + \frac{c _{1} t ^{2}}{4} + \frac{c _{1}^{2}}{4}

Schritte zur Lösung

\frac{d x}{d t} = t x

Solve separable ODE:

x = \frac{t ^{4}}{16} + \frac{c _{1} t ^{2}}{4} + \frac{c _{1}^{2}}{4}

x = \frac{t ^{4}}{16} + \frac{c _{1} t ^{2}}{4} + \frac{c _{1}^{2}}{4}

y^{^{'}} = (1 - 13 x) y^{2}, y (0) = - \frac{1}{4}

y^{^{'}} + \frac{y}{6} = 5, y (- 1) = 0

100 y + 0.01 y^{^{'}} = 500

\frac{d y}{d x} y = 7 x^{3}

\frac{d Q}{d t} + \frac{1}{50} Q = 0.2