5y^'=ycos(x),y(0)=2

Lösung

5 y^{^{'}} = y cos (x), y (0) = 2

y = 2 e^{\frac{s i n ( x )}{5}}

Schritte zur Lösung

5 y^{'} (x) = y cos (x)

Solve separable ODE:

y = 2 e^{\frac{s i n ( x )}{5}}

y = 2 e^{\frac{s i n ( x )}{5}}

\frac{d v}{d t} = 9.81 - 3 v

y^{^{'}} = x y^{2} sin (x^{2})

\frac{d v}{d t} = 2 - 4 v

\frac{d r}{d s} = e^{r + s}

\frac{d y}{d x} x = y^{2}