(dv)/(du)=tan(v)

Lösung

\frac{d v}{d u} = tan (v)

v = arcsin (e^{u + c_{1}}) + 2 πn, v = π + arcsin (- e^{u + c_{1}}) + 2 πn

Schritte zur Lösung

\frac{d v}{d u} = tan (v)

Solve separable ODE:

v = arcsin (e^{u + c_{1}}) + 2 πn, v = π + arcsin (- e^{u + c_{1}}) + 2 πn

v = arcsin (e^{u + c_{1}}) + 2 πn, v = π + arcsin (- e^{u + c_{1}}) + 2 πn

\frac{d y}{d t} + 10 y = 15

\frac{d R}{d x} = a (R^{2} + 4)

(x^{2} + 3) \frac{d y}{d x} = x e^{y}, y (1) = 0

y \cdot y^{^{'}} + 4 x - 2 = 0

\frac{d y}{d t} = - 0.4 (y - 70)