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Frequently Asked Questions (FAQ)
What is the d/(dy)(1/(y^3+4y^2)) ?
- The d/(dy)(1/(y^3+4y^2)) is -(3y+8)/(y^3(y+4)^2)
What is the first d/(dy)(1/(y^3+4y^2)) ?
- The first d/(dy)(1/(y^3+4y^2)) is -(3y+8)/(y^3(y+4)^2)