y^'=x(1-y)

Lösung

y^{^{'}} = x (1 - y)

y = - e^{- \frac{x ^{2}}{2} - c_{1}} + 1

Schritte zur Lösung

y^{'} (x) = x (1 - y)

Solve separable ODE:

y = - e^{- \frac{x ^{2}}{2} - c_{1}} + 1

y = - e^{- \frac{x ^{2}}{2} - c_{1}} + 1

y^{^{'}} = 4 y + 16 x y

\frac{d y}{d x} = x y^{2} sin (x^{2}), y (0) = 1

\frac{d y}{d x} = 3 y + k

y^{^{'}} = \frac{sin ( y )}{x}

d y = \frac{y + 1}{x + 4} d x