y^'y+36x=0

Lösung

y^{^{'}} y + 36 x = 0

y = - 36 x^{2} + c_{1}, y = - - 36 x^{2} + c_{1}

Schritte zur Lösung

y^{'} (x) y + 36 x = 0

Solve separable ODE:

y = - 36 x^{2} + c_{1}, y = - - 36 x^{2} + c_{1}

y = - 36 x^{2} + c_{1}, y = - - 36 x^{2} + c_{1}

y^{^{'}} + t y = 3 t y^{2}

\frac{d y}{d x} = \frac{1}{x ^{2} y ^{2}}, y (1) = 1

y^{^{'}} = a - y^{2}

(x^{2} + 1) y^{^{'}} = (y^{2} + 1) x

x^{^{'}} + \frac{3}{200} x = 0.006