(dx)/(dy)=2yx^2+2y

解答

\frac{d x}{d y} = 2 y x^{2} + 2 y

x = tan (y^{2} + c_{1})

求解步骤

\frac{d x}{d y} = 2 y x^{2} + 2 y

求解可分离方程:

x = tan (y^{2} + c_{1})

x = tan (y^{2} + c_{1})

(t^{2} - 16 t + 15) y^{^{'}} = y

y^{^{'}} = (1 - 2 x) y^{2}, y (0) = \frac{- 1}{6}

\frac{d y}{d x} - y^{5} = 0, y (0) = 1

2 (x^{2} + 1) \frac{d y}{d x} = x (4 - y^{2})

(1 + x^{2}) \frac{d y}{d x} + 2 x y = - x, x > 0