y^'=2-0.1y,y(0)=0

Lösung

y^{^{'}} = 2 - 0.1 y, y (0) = 0

y = - 20 e^{- \frac{t}{10}} + 20

Schritte zur Lösung

y^{'} (t) = 2 - 0.1 y

Solve separable ODE:

y = - 20 e^{- \frac{t}{10}} + 20

y = - 20 e^{- \frac{t}{10}} + 20

x^{^{'}} = \frac{1 + x ^{2}}{1 + t ^{2}}

e^{x} d x - 2 y d y = 0

\frac{d y}{d x} = 1 + y^{2}

x \frac{d y}{d x} = y + 6 x y

\frac{d y}{d x} = \frac{( 1 + x )}{x y}