(dy)/(dx)y=tan(x^2+1)

Lösung

\frac{d y}{d x} y = tan (x^{2} + 1)

y = 2 \cdot \int tan (x^{2} + 1) d x, y = - 2 \cdot \int tan (x^{2} + 1) d x

Schritte zur Lösung

\frac{d y}{d x} y = tan (x^{2} + 1)

Solve separable ODE:

y = 2 \cdot \int tan (x^{2} + 1) d x, y = - 2 \cdot \int tan (x^{2} + 1) d x

y = 2 \cdot \int tan (x^{2} + 1) d x, y = - 2 \cdot \int tan (x^{2} + 1) d x

\frac{d y}{d x} = x \cdot e^{- y}

x d y = (y^{- 3} - y) d x

\frac{d y}{d t} = 2 t y

x \frac{d y}{d x} + 6 y = 3 x y

y^{^{'}} = - 0.2 y, y (0) = c e^{0.2 t}