y^'+5y=-10

Lösung

y^{^{'}} + 5 y = - 10

y = e^{- 5 t + c_{1}} - 2

Schritte zur Lösung

y^{'} (t) + 5 y = - 10

Solve separable ODE:

y = e^{- 5 t + c_{1}} - 2

y = e^{- 5 t + c_{1}} - 2

\frac{d y}{d t} = - 4 y, y = π

\frac{d y}{d x} = - \frac{sin ( x )}{2 y ^{2}}

(x^{2} + 16) y^{^{'}} = x y

y^{^{'}} = - 2 x y^{4}

t y^{^{'}} + 2 y = 1