xf^'(x)=(f(x))^2

Lösung

x f^{^{'}} (x) = (f (x))^{2}

f (x) = - \frac{1}{ln ( x ) + c _{1}}

Schritte zur Lösung

x f^{'} (x) = (f (x))^{2}

Solve separable ODE:

f (x) = - \frac{1}{ln ( x ) + c _{1}}

f (x) = - \frac{1}{ln ( x ) + c _{1}}

\frac{d y}{d x} = 8 x y - 12 x^{2} y

x^{2} + 1 d x - 3 y d y = 0

x^{^{'}} = x^{2} t

y \cdot d x = (- 1 + x) d y

e^{- 2 y} \frac{d y}{d x} = x - 2