y^'=5y-4

Lösung

y^{^{'}} = 5 y - 4

y = \frac{e ^{5 t + c_{1}}}{5} + \frac{4}{5}

Schritte zur Lösung

y^{'} (t) = 5 y - 4

Solve separable ODE:

y = \frac{e ^{5 t + c_{1}}}{5} + \frac{4}{5}

y = \frac{e ^{5 t + c_{1}}}{5} + \frac{4}{5}

y^{^{'}} = 5 y - 3

\frac{d y}{d x} = \frac{y + 1}{x + 1}

\frac{d x}{d t} = 80 - \frac{x}{100}, x = 4000, t = 0

\frac{d y}{d x} = x (y - 2)

\frac{d y}{d t} = \frac{3 t ^{2} + 4 t + 2}{2 ( y - 1 )}